1x^2-42=37x

Solution for 1x^2-42=37x equation:

1x^2-42=37x

We move all terms to the left:

1x^2-42-(37x)=0

We add all the numbers together, and all the variables

x^2-37x-42=0

a = 1; b = -37; c = -42;
Δ = b2-4ac
Δ = -372-4·1·(-42)
Δ = 1537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{1537}}{2*1}=\frac{37-\sqrt{1537}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{1537}}{2*1}=\frac{37+\sqrt{1537}}{2}
$